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For a square there are four, for a regular pentagon there are 11, for a regular hexagon there are 24 and for a regular heptagon there are 50. What are they and how many are there for a regular octagon?
Question
#121967. Asked by gmackematix. (Jun 16 11 7:56 PM)
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Watchkeeper
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The answer is indeed 80, but the internal shapes are not necessarily triangles. The pentagon, for example, has another pentagon created inside it by the diagonals and an octagon has a hexagon at the centre.
The equation for calculating the number of internal shapes is horrendous:
http://mathworld.wolfram.com/RegularPolygonDivisionbyDiagonals.html
Fortunately, the author of the Webpage lists the numbers as being 1 (triangle), 4 (square), 11 (pentagon), 24 (hexagon), 50 (heptagon), 80 (octagon), 154 (nonagon), 220 (decagon) and 375 (hendecagon).
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gmackematix
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Yay, you have between you, QP and Watchkeeper, correctly joined all the dots. They are the number of separate areas a polygon is divided into by its diagonals, which for a regular octagon is 80.
I think the formula is correct and shows that, just because a problem is easy to state doesn't mean the maths will be simple (see the circumference of an ellipse).
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