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    A couple has sons and daughters. Each son has an equal number of brothers and sisters. Each daughter has twice more brothers than sistes. How many sons and daughters does the couple have?

    Question #21604. Asked by %BF?.

    Gnomon

    		Four sons, three daughters. Each son has three brothers and three sisters. Each daughter has four brothers and two sisters.

    Aug 19 02, 10:40 PM
    Bob(TM)

    		This is an excellent elementary algebra problem: two equations and two unknowns.

    Every daughter has twice as many brothers as sisters: b = 2 * (s - 1)
    Every son has an equal number of brothers and sisters: s = (b - 1)

    where s is (s)ister and b is (b)rother.

    Note the 'minus {1';} from each siblings perspective, there is one less of their gender - they don't include themselves.

    Substitute the second into the first:

    b = 2 * (b - 1 - 1) = 2 * (b - {2);} b = 2b - 4 ===%3E b = 4

    Substitute the result above into the second equation:

    s = 4 - 1 ===%3E s = 3

    Four brothers and three sisters.





    Aug 20 02, 7:43 PM
    3

    		hu?

    Feb 15 03, 3:41 AM

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