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Distribute nine marbles in four boxes so that each box contains an odd number of marbles, different from the three other boxes. You must use all nine?

Question #24081. Asked by Tim. (Nov 08 02 4:15 AM)

Friar Tuck

Put two marbles in the three biggest boxes and three in the smallest box. Then put the boxes inside each other so that the smallest box only has three marbles. The next largest has a total of five. the next has seven and the largerst has nine.

 Nov 08 02, 7:56 AM
shawn888

You should divide them as 5, 3, 1 and 0 which adds up to 9 and all are odd and unequal numbers.

 Jul 15 04, 3:07 AM

 There is a quiz show with three boxes...two contain nothing and one contains {\$1,000,000.} The contestant is asked to choose one of the boxes, which he does. Of the two remaining boxes that he didn't choose, one is removed which contains nothing. There are now 2 boxes left: one contains {\$1,000,000} and the other contains nothing. Assuming the contestant wants to win the {\$1,000,000,} is it best to: a)keep the box he chose to begin with, b)change to the other box, or c) it makes no difference to the odds what he does ... and why?

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