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    A character in an alphabet is represented in 12 bits. How many characters are there in the alphabet which do not have any sequence of 3 adjacent 1s?

    Question #63386. Asked by ajay_daiict. (Mar 12 06 1:19 AM)


    Perderabo

    From 000000000000 to 111111111111 (inclusive) is a list of 4096 binary numbers. A quick program to generate that list and remove instances of 3 adjacent 1s results in a list of 1705 entries. The few and last few:


    000000000000 110110101000
    000000000001 110110101001
    000000000010 110110101010
    000000000011 110110101011
    000000000100 110110101100
    000000000101 110110101101
    000000000110 110110110000
    000000001000 110110110001
    000000001001 110110110010
    000000001010 110110110011
    000000001011 110110110100
    000000001100 110110110101
    000000001101 110110110110



    Mar 12 06, 5:21 AM
    xfacilitatorx

    Alphabet in Binary Code
    Letter
    Binary Code

    A 01000001
    B 01000010
    C 01000011
    D 01000100
    E 01000101
    F 01000110
    G 01000111
    H 01001000
    I 01001001
    J 01001010
    K 01001011
    L 01001100
    M 01001101
    N 01001110
    O 01001111
    P 01010000
    Q 01010001
    R 01010010
    S 01010011
    T 01010100
    U 01010101
    V 01010110
    W 01010111
    X 01011000
    Y 01011001
    Z 01011010

    http://www.tekmom.com/buzzwords/binaryalphabet.html

    http://www.tekmom.com/buzzwords/binaryalphabet.html



    Mar 12 06, 1:45 PM


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