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    Under standard Monopoly rules, what is the most amount of money a player can lose in a single turn?

    Question #68999. Asked by darkpresence. (Jul 29 06 4:59 PM)


    gdec1

    Without rolling doubles and landing on multiple improved properties, the most rent a player would have to pay is $2000- Boardwalk with a hotel.

    http://www.travelertags.com/photos/62007.jpg

    Jul 29 06, 5:44 PM
    paper_aero

    Guessing if many hotels / houses are owned and picked up building repairs card (I can't find exact figures) then the multiple could be higher than 2000

    Jul 29 06, 5:52 PM
    gdec1

    Building repairs are $25 for each house & $100 for each hotel. If you owned all 12 hotels and all 32 houses in the game, the total repair bill would be $2000 exactly.
    http://www.mospaw.com/monopoly/rules-monopoly.shtml

    Jul 29 06, 6:18 PM
    peasypod

    Well, there is that income tax square to land on. And if some Einstein preferred to pay 10% of his mountain of cash rather than the $200, it may be more than $2000...

    Jul 29 06, 6:42 PM
    paper_aero

    I thought building repairs were higher,
    Assessed For Street Repairs -- $40 Per House, $115 Per Hotel - sorry.


    Jul 29 06, 6:55 PM
    darkpresence

    Gonna have to get out the monopoly board! Let's assume two rolls of doubles and all property with hotels.

    Jul 31 06, 3:45 PM
    Baloo55th

    Can't find my board, but it is possible to land on both Park Lane and Mayfair with a double 1, and they're the most expensive hotels to land on. So what would be the most expensive thing a double throw back from that? Would it be the repairs card or another hotel? If the repairs card is possible, and you had hotels on everything else other than Mayfair and Park Lane, that would give the maximum loss. If that card isn't a double back from Park Lane, then it will have to be one of the green streets with a hotel on it.

    Aug 01 06, 4:06 AM


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