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    For any two random letters of the English alphabet, what is the chance they are next to each other on a QWERTY keyboard?

    Question #97741. Asked by jimmycarlos. (Jul 20 08 7:14 PM)


    davejacobs

    		The keyboard has 26 letters, six of which have only one neighbour, the other 20 having two, one each side.
    Thus the number of neighbours in total is 20x2 + 6, or 46.
    Choosing a letter at random, the odds of a second letter chosen at random being a neighbour of the first is 1 in 46
    I think!


    Jul 21 08, 12:46 AM
    balldude88

    		For the 20 that have two letters touching them there is a 2/25 chance of drawing a lateral letter. For the 6 that have one side there is a 1/25 chance.

    So to figure the total chance you would do (20/26)X(2/25)+(6/26)*(1/25)= .0708

    Which means there is a little less than a 1/14 chance that the two letters chosen are next to each other.

    Jul 21 08, 1:04 AM

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