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Logics And Riddles V Trivia Quiz

Part five in the series. I hope it's not too tough. Have fun.

A multiple-choice quiz by wimm. Estimated time: 5 mins.

Author
wimm

Time
5 mins

Type
Multiple Choice

Quiz #
90,652

Updated
Dec 03 21

# Qns
5

Difficulty
Tough

Avg Score
3 / 5

Plays
13562

Question 1 of 5

1. Give the next number in this sequence:

10, 30, 68, 130, 222, ?

Answer: (a number)

NEXT>

Question 2 of 5

2. Roman numbers: give the next one in this series:

MMMMXCVI, CCLVI, MXXIV, LXIV, CCLVI, ? Hint

XIV

LVI

XVI

XXVIII

NEXT>

Question 3 of 5

3. What would be the value of A, B and C. The sum of the rows and columns must equal the given values?

C...A...B...40

A...A...B...33

C...C...C...60

53.46.34

Answer: (number, number, number- be sure they are in correct order; A B C!)

4. There are 100 people at a party. There is AT LEAST one woman in the room. And if you pick at random two people, there will ALWAYS be at least one man picked. Knowing this, you can tell me how many men are present at the party?

Answer: (a number)

NEXT>

Question 5 of 5

5. What is the next number?

0, 2, 6, 12, 20, 30, 42, 56, ?

Answer: (a number)

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Quiz Answer Key and Fun Facts

1. Give the next number in this sequence:

10, 30, 68, 130, 222, ?

Answer: 350

The rule: n x n x n +n. starting with n=2, 2x2x2+2=10, 3x3x3+3=30, ... We want 7x7x7+7=350.

another way to get there as proposed by alessandrot:
"difference between number: 20 - 38 - 62 - 92
difference between this number: 18 - 24 - 30
so 24-18=6, 30-24=6, then 6 is the sequencial:
30 + 6 = 36 and 36 + 92 = 128
if I get 128 and sum with 222 the number will be: 350"

2. Roman numbers: give the next one in this series:

MMMMXCVI, CCLVI, MXXIV, LXIV, CCLVI, ?

Answer: XVI

The series reads: 4096, 256, 1024, 64, 256, ?
So the rule is :16 x4.
We want 256:16 = 16 = XVI

3. What would be the value of A, B and C. The sum of the rows and columns must equal the given values?

C...A...B...40
A...A...B...33
C...C...C...60
53.46.34

Answer: 13, 7, 20

The first row would be 20 + 13 + 7 = 40. And so on, and so on...

Answer: 99

Suppose there are two women (or more) present. You could pick them at random together, and then there wouldn't be at least one man in the randomly picked duo. So there can be only 1 woman at the party.

5. What is the next number?

0, 2, 6, 12, 20, 30, 42, 56, ?

Answer: 72

Different ways to get there. Starting with n=1, it's the series n squared minus n. For n=9 this becomes 9x9-9=72.
Another way: the series is the previous number +2,+4,+6,+8,+10,...

Source: Author wimm

This quiz was reviewed by FunTrivia editor crisw before going online.
Any errors found in FunTrivia content are routinely corrected through our feedback system.

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