There is a nine digit number in which each of the digits from 1 to 9 appears once. The whole number is divisible by 9. If you remove the rightmost number, the remaining 8 digit number is divisible by 8. Remove the rightmost number, and the remaining 7 digit number is divisible by 7.This pattern continues down to a single digit. What is the number?

5th digit must be 5 and presumed last digit had to be 9, trial and error
381654729

Hi Gtho4

you're absolutely right....I'll have to make it harder next time

Dumpling

[This message has been edited by dumpling (edited 01-27-2001).]