There are 100 buildings along a street. A sign maker is ordered to number the buildings from 1 to 100. How many '9's' will he need?

Dunc	11 nines (9,19,29,39,49,59,69,79,89,99) + (remember 2 9s in 99) 9 nines (90,91,92,93,94,95,96,97,98) ------- 20 nines Nov 05 02, 5:50 AM

Son of The Household Cavalry

None as he would bulk buy 6s Nov 05 02, 7:43 AM

masocc

masocc says: Unless of course, you're only talking about 100 buildings along ONE SIDE of a street. In which case, you could only number 49 or 50 of the buildings (depending on whether you chose odd or even numbers). Odd numbers would equal 15 9's, while even would yield only 5 9's. Or something. Tue Nov 05 00:13:05 CST 2002 (Delete Entry) (Reposted to fix typo - McG) Nov 14 02, 8:21 AM