1. When given a relatively basic quadratic question such as x^2 + 9x + 20, which of these options is a suitable way to solve it? Collaborating Factorising Derivatising Collating

2. What would be the two constituents of the following quadratic question: x^2 + x - 6? (x+6) and (x+5) (x+4) and (x+4) (x+3) and (x-2) (x+3) and (x+2)

3. Basic arithmetic will be important in your attempt to solve the next question. What are the two constituents of x^2 - 9x + 18? (x+3) and (x+6) (x-3) and (x+6) (x+3) and (x-6) (x-3) and (x-6)

4. Quadratics are not always basic and often the x^2 term will have a co-efficient greater than 1. What are the two components of the following: 3x^2 + 9x + 6? (There are other possibilities, however, only one of the following answers is correct) (3x+1) and (x+5) (3x+1.5) and (x+4) (3x+3) and (x+2) (3x-3) and (x-2)

5. An equation is a phrase which contains an equals (=) sign and is therefore able to be solved to give roots (answers). In quadratics there are ALWAYS two answers. Solve the following equation: x^2 - 4x + 4 = 0. x = 3, x = 1 x = 3, x = 2 x = 2, x = 2 x = 4, x = 1

6. Solve the following quadratic equation: x^2 + 2x - 8 = 0. x = -3, x = 3 x = 1, x = -6 x = 2, x = 2 x = -4, x = 2

7. In those dreaded maths examinations, students are often given the components and are asked to find the original quadratic expression. Find the expression from the following constituents: (x+8) and (x-3). x^2 + 11x + 24 x^2 + 3x + 5 x^2 + 3x - 11 x^2 + 5x - 24

8. Find the expression from the given components: (x-6) and (x-4). x^2 + 10x - 24 x^2 - 10x - 24 x^2 - 10x + 24 x^2 + 10x + 24

9. The topic of quadratics does indeed have an equation, and boy is it an equation! X = -b ? (?) / 2a. Within this equation you will see a missing portion indicated by a question mark in brackets/parentheses. (?) = the square root of what? d^2 + 4bd c^2 - 4bc b^2 - 4ac a^2 + 4af

10. Quadratic equations can also be shown graphically. If the quadratic expression was positive: y = 3x^2 + x - 2, what shape would the graphical curve be? All of these n u c