A multiple-choice quiz
by angikar.
Estimated time: 22 mins.

Quiz Answer Key and Fun Facts

Answer:
**2 **

Look at equation no. 2 in question 7 and equation no. 2 of question no. 5.

As per equation no. 2 in question 7,

there are two possibilities.

1) sansut = 0 yanji = no definite value as of now (A * 0 = 0)

2) yanji = 1 sansut = no definite value as of now (1 * B = B)

But, madzikumite/sansut = kumite

Therefore, sansut is not equal to 0. Therefore, the first option is wrong.

Hence, yanji = 1.

Also, somaru is the successor of baduka.

Now, look at the equation in question 10. somaru + yanji = baduka + kumite

Therefore,

baduka + yanji + yanji = baduka + kumite

or,

kumite = yanji + yanji = 2

Therefore, finally,

kumite * yanji = 2 * 1 = 2

Look at equation no. 2 in question 7 and equation no. 2 of question no. 5.

As per equation no. 2 in question 7,

there are two possibilities.

1) sansut = 0 yanji = no definite value as of now (A * 0 = 0)

2) yanji = 1 sansut = no definite value as of now (1 * B = B)

But, madzikumite/sansut = kumite

Therefore, sansut is not equal to 0. Therefore, the first option is wrong.

Hence, yanji = 1.

Also, somaru is the successor of baduka.

Now, look at the equation in question 10. somaru + yanji = baduka + kumite

Therefore,

baduka + yanji + yanji = baduka + kumite

or,

kumite = yanji + yanji = 2

Therefore, finally,

kumite * yanji = 2 * 1 = 2

Answer:
**3 **

First, look at equation no. 1 of question 1.

laken = somaru + yanji

or, laken = somaru + 1

Therefore, laken is the successor of somaru, which is the successor of baduka.

or, laken = baduka + 2

Now, look at equation no. 2 in question 1 and equation no. 2 in question 5.

madzi = kumite * laken

madzi = 2 * laken

Also,

madzikumite/sansut = kumite

or, madzikumite = 2 * sansut

Now, notice that madzikumite is starting with 'madzi'. We have been told that the code follows a similar system as English. How do we express numbers greater than nine? We specify the multiple of ten and then, the units digit, e.g., 'sixty + seven = sixtyseven'; 'seventy + three = seventythree'.

Therefore, madzi is a multiple of ten like ten, twenty, thirty, etc. Madzikumite must mean 'madzi + kumite', or 'madzi + 2'. For example, twentytwo = twenty + two. However, we do not know the exact value of 'madzi'. We shall know it later. But, at this stage, we know that it is a multiple of ten.

Anyways, we have madzi + kumite = 2 * sansut

or, 2 * laken + 2 = 2 * sansut

Dividing by 2 on both sides,

We have,

laken + 1 = sansut

or, baduka + 2 + 1 = sansut

or, sansut - baduka = 3

To solve the next questions, we can now break the numbers like sindikumite as (sindi + kumite); merasansut as 'mera + sansut'.

Now, we need to get the unit digits of baduka, somaru, laken and sansut.

Since, laken is a factor of a multiple of ten, its unit digit is either 5 or 0.

If its unit digit is 0, the units digit of sansut becomes 1. Since, sansut is not equal to 1, it is either 11, 21, 31, etc. But, those numbers violate the principles given before (yanji is 1, hence such numbers should be like 'madziyanji', 'sindiyanji', etc). Hence, this is wrong.

Laken's unit digit is 5.

Therefore, baduka, somaru, laken, sansut must be '3, 4, 5, 6' or '13, 14, 15, 16' or '23, 24, 25, 26', etc.

First, look at equation no. 1 of question 1.

laken = somaru + yanji

or, laken = somaru + 1

Therefore, laken is the successor of somaru, which is the successor of baduka.

or, laken = baduka + 2

Now, look at equation no. 2 in question 1 and equation no. 2 in question 5.

madzi = kumite * laken

madzi = 2 * laken

Also,

madzikumite/sansut = kumite

or, madzikumite = 2 * sansut

Now, notice that madzikumite is starting with 'madzi'. We have been told that the code follows a similar system as English. How do we express numbers greater than nine? We specify the multiple of ten and then, the units digit, e.g., 'sixty + seven = sixtyseven'; 'seventy + three = seventythree'.

Therefore, madzi is a multiple of ten like ten, twenty, thirty, etc. Madzikumite must mean 'madzi + kumite', or 'madzi + 2'. For example, twentytwo = twenty + two. However, we do not know the exact value of 'madzi'. We shall know it later. But, at this stage, we know that it is a multiple of ten.

Anyways, we have madzi + kumite = 2 * sansut

or, 2 * laken + 2 = 2 * sansut

Dividing by 2 on both sides,

We have,

laken + 1 = sansut

or, baduka + 2 + 1 = sansut

or, sansut - baduka = 3

To solve the next questions, we can now break the numbers like sindikumite as (sindi + kumite); merasansut as 'mera + sansut'.

Now, we need to get the unit digits of baduka, somaru, laken and sansut.

Since, laken is a factor of a multiple of ten, its unit digit is either 5 or 0.

If its unit digit is 0, the units digit of sansut becomes 1. Since, sansut is not equal to 1, it is either 11, 21, 31, etc. But, those numbers violate the principles given before (yanji is 1, hence such numbers should be like 'madziyanji', 'sindiyanji', etc). Hence, this is wrong.

Laken's unit digit is 5.

Therefore, baduka, somaru, laken, sansut must be '3, 4, 5, 6' or '13, 14, 15, 16' or '23, 24, 25, 26', etc.

Answer:
**15 **

To solve this, we need to know the tens digit of baduka, somaru, laken and sansut.

Now, look at equation no. 1 of question 4 and equation no. 1 of question 6.

somaru * somaru = madzisansut

somaru * baduka = madzikumite

these are in the form of

A4 * A4 = B6

A4 * A3 = B2

[Note: A4 does not mean A * 4. A and B are only to state the tens digit.]

Now, see If A = 1,

14 * 13 = 182

14 * 14 = 196

if A = 2,

24 * 23 = 552

24 * 24 = 576

As A's value increases, the tens digit are not only different but the difference is also increasing.

To ensure that (A4 * A4) and (A4 * A3) have the same tens digit, we need to ensure that A4 is less than 10. Otherwise, to get (A4 * A4) from (A4 * A3), we would add a number greater than 10, changing the tens digit. Therefore, A4 is a single digit number. A = 0. hence, B = 1

Therefore, we get the tens digit of baduka, somaru, laken, sansut.

baduka = 3

somaru = 4

laken = 5

sansut = 6

Therefore, madzi = 2 * laken = 10

Now, baduka * laken = 3 * 5 = 15

To solve this, we need to know the tens digit of baduka, somaru, laken and sansut.

Now, look at equation no. 1 of question 4 and equation no. 1 of question 6.

somaru * somaru = madzisansut

somaru * baduka = madzikumite

these are in the form of

A4 * A4 = B6

A4 * A3 = B2

[Note: A4 does not mean A * 4. A and B are only to state the tens digit.]

Now, see If A = 1,

14 * 13 = 182

14 * 14 = 196

if A = 2,

24 * 23 = 552

24 * 24 = 576

As A's value increases, the tens digit are not only different but the difference is also increasing.

To ensure that (A4 * A4) and (A4 * A3) have the same tens digit, we need to ensure that A4 is less than 10. Otherwise, to get (A4 * A4) from (A4 * A3), we would add a number greater than 10, changing the tens digit. Therefore, A4 is a single digit number. A = 0. hence, B = 1

Therefore, we get the tens digit of baduka, somaru, laken, sansut.

baduka = 3

somaru = 4

laken = 5

sansut = 6

Therefore, madzi = 2 * laken = 10

Now, baduka * laken = 3 * 5 = 15

Answer:
**30 **

Till now, we have got the codes for 1, 2, 3, 4, 5, 6, 10. We do not know yet the codes of 7, 8, 9.

Therefore, we can now break the other codes like this example : verishlaken = verish + 5

We now see that drasme, verish, singa, trita, mera, yentu, shupop and sindi as the codes of twenty, thirty, forty, fifty, sixty, seventy, eighty and ninety in random order. We shall match them very soon.

This question is similar to the previous question.

sansut * laken = 6 * 5 = 30

Note that we do not know the exact code of 30. However, we know that it must one between drasme, verish, singa, trita, mera, yentu, shupop and sindi.

Till now, we have got the codes for 1, 2, 3, 4, 5, 6, 10. We do not know yet the codes of 7, 8, 9.

Therefore, we can now break the other codes like this example : verishlaken = verish + 5

We now see that drasme, verish, singa, trita, mera, yentu, shupop and sindi as the codes of twenty, thirty, forty, fifty, sixty, seventy, eighty and ninety in random order. We shall match them very soon.

This question is similar to the previous question.

sansut * laken = 6 * 5 = 30

Note that we do not know the exact code of 30. However, we know that it must one between drasme, verish, singa, trita, mera, yentu, shupop and sindi.

Answer:
**7 **

Breaking the codes like given previously, we see that 7, 8, 9 must stand for lemu, rackim and vicolaf in random order. We are going to match the values soon.

Look at equation no. 1 of question 7.

rackim = verishlaken - madzisansut

or, rackim = C5 - 16 [C stands for the tens digit of verish]

But, rackim stand for a single digit. Therefore, C5 = 25 25-16 = 9

Hence, verish = 20 rackim = 9

Now, verishyanji = verish + yanji = 21 baduka = 3

21/3 = 7

As of now, we do not know the code for seven. But we know that it is either vicolaf or lemu.

Breaking the codes like given previously, we see that 7, 8, 9 must stand for lemu, rackim and vicolaf in random order. We are going to match the values soon.

Look at equation no. 1 of question 7.

rackim = verishlaken - madzisansut

or, rackim = C5 - 16 [C stands for the tens digit of verish]

But, rackim stand for a single digit. Therefore, C5 = 25 25-16 = 9

Hence, verish = 20 rackim = 9

Now, verishyanji = verish + yanji = 21 baduka = 3

21/3 = 7

As of now, we do not know the code for seven. But we know that it is either vicolaf or lemu.

Answer:
**9 **

Look at equation 2 of question no. 9. We will be able to get the values of both singa and lemu.

We get,

3 + 2D = E1

Here, D is the value of lemu. It must be either 7 or 8, as these are the only single digit numbers whose code we do not know yet. E is the tens digit of singa.

However,

3 + 28 = 31

3 + 27 = 30

In both cases, the tens digit of the sum is 3. Hence, singa = 30

But, only the first of the possibilities gives us 1 as the unit digit. 3 + 28 = 31

Hence, lemu = 8

Now, singasansut = 36 somaru = 4 Hence,

36/4 = 9

Look at equation 2 of question no. 9. We will be able to get the values of both singa and lemu.

We get,

3 + 2D = E1

Here, D is the value of lemu. It must be either 7 or 8, as these are the only single digit numbers whose code we do not know yet. E is the tens digit of singa.

However,

3 + 28 = 31

3 + 27 = 30

In both cases, the tens digit of the sum is 3. Hence, singa = 30

But, only the first of the possibilities gives us 1 as the unit digit. 3 + 28 = 31

Hence, lemu = 8

Now, singasansut = 36 somaru = 4 Hence,

36/4 = 9

Answer:
**0 **

Since lemu is the code of eight, vicolaf must be the code of seven.

Now, look at clue no. 2 in question 8.

We have

lemu + madzilaken = verishbaduka - nudez

or,

8 + 15 = 23 - nudez

Therefore, nudez = 0

Therefore, nudez * rackim = 0 [Multiplication by zero yields zero.]

Since lemu is the code of eight, vicolaf must be the code of seven.

Now, look at clue no. 2 in question 8.

We have

lemu + madzilaken = verishbaduka - nudez

or,

8 + 15 = 23 - nudez

Therefore, nudez = 0

Therefore, nudez * rackim = 0 [Multiplication by zero yields zero.]

Answer:
**10 **

First look at equation no. 1 of question 5.

vicolaf * vicolaf = tritarackim

or, 7 * 7 = 49 = trita + rackim = trita + 9

Hence, trita = 40

This equation is easy to solve.

We have,

madzikumite = 10 + 2 = 12

madzilaken = 10 + 5 = 15

madzilemu = 10 + 8 = 18

12 * 15 = 180

180/18 = 10

First look at equation no. 1 of question 5.

vicolaf * vicolaf = tritarackim

or, 7 * 7 = 49 = trita + rackim = trita + 9

Hence, trita = 40

This equation is easy to solve.

We have,

madzikumite = 10 + 2 = 12

madzilaken = 10 + 5 = 15

madzilemu = 10 + 8 = 18

12 * 15 = 180

180/18 = 10

Answer:
**2 **

Till now, we know the codes for 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 20, 30 and 40.

Now, look at equation 2 of question 2.

We have madziyanji * rackim = drasmerackim

Therefore, 11 * 9 = 99 = drasme + rackim = drasme + 9

Hence, drasme = 90

Now, look at equation 2 of question 6.

We have

tritasansut + vicolaf = merabaduka

Hence, (40 + 6) + 7 = mera + 3

or, 53 = mera + 3

Hence, mera = 50

Now, look at the equation of question 3.

sindivicolaf - shupopbaduka = yentulemu - sindisomaru

Hence, sindi + 7 - (shupop + 3) = yentu + 8 - (sindi + 4)

or, sindi + 7 - shupop - 3 = yentu + 8 - sindi -4

or, sindi - shupop = yentu - sindi

Since both the expressions are greater than 0,

yentu > sindi > shupop

But, these three are the codes of 60, 70 ,80 in any order.

Hence, yentu = 80 sindi = 70 shupop = 60

Therefore, yentusomaru = yentu + somaru = 80 + 4 = 84

tritakumite = trita + kumite = 40 + 2 = 42

84/42 = 2

Till now, we know the codes for 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 20, 30 and 40.

Now, look at equation 2 of question 2.

We have madziyanji * rackim = drasmerackim

Therefore, 11 * 9 = 99 = drasme + rackim = drasme + 9

Hence, drasme = 90

Now, look at equation 2 of question 6.

We have

tritasansut + vicolaf = merabaduka

Hence, (40 + 6) + 7 = mera + 3

or, 53 = mera + 3

Hence, mera = 50

Now, look at the equation of question 3.

sindivicolaf - shupopbaduka = yentulemu - sindisomaru

Hence, sindi + 7 - (shupop + 3) = yentu + 8 - (sindi + 4)

or, sindi + 7 - shupop - 3 = yentu + 8 - sindi -4

or, sindi - shupop = yentu - sindi

Since both the expressions are greater than 0,

yentu > sindi > shupop

But, these three are the codes of 60, 70 ,80 in any order.

Hence, yentu = 80 sindi = 70 shupop = 60

Therefore, yentusomaru = yentu + somaru = 80 + 4 = 84

tritakumite = trita + kumite = 40 + 2 = 42

84/42 = 2

Answer:
**169**

Finally, look at equation 1 of question 2. pikash = kumite * mera = 2 * 50 = 100

Hence, pikash + shupoprackim = 100 + 69 = 169

Finally,

we have:

nudez = 0

yanji = 1

kumite = 2

baduka = 3

somaru = 4

laken = 5

sansut = 6

vicolaf = 7

lemu = 8

rackim = 9

madzi = 10

verish = 20

singa = 30

trita = 40

mera = 50

shupop = 60

sindi = 70

yentu = 80

drasme = 90

pikash = 100

The uncoded clue equations are:

Question 1: 5 = 4 + 1. 10 = 2 * 5.

Question 2: 2 * 50 = 100. 11 * 9 = 99

Question 3: 77 - 63 = 88 - 74 > 0

Question 4: 4 * 4 = 16

Question 5: 7 * 7 = 49. 12/6 = 2

Question 6: 4 * 3 = 12. 56 + 7 = 63

Question 7: 9 = 25 - 16. 1 * 6 = 6

Question 8: 3 + 1 = 4. 8 + 15 = 23 - 0

Question 9: 3 + 28 = 31

Question 10: 4 + 1 = 3 + 2

Finally, look at equation 1 of question 2. pikash = kumite * mera = 2 * 50 = 100

Hence, pikash + shupoprackim = 100 + 69 = 169

Finally,

we have:

nudez = 0

yanji = 1

kumite = 2

baduka = 3

somaru = 4

laken = 5

sansut = 6

vicolaf = 7

lemu = 8

rackim = 9

madzi = 10

verish = 20

singa = 30

trita = 40

mera = 50

shupop = 60

sindi = 70

yentu = 80

drasme = 90

pikash = 100

The uncoded clue equations are:

Question 1: 5 = 4 + 1. 10 = 2 * 5.

Question 2: 2 * 50 = 100. 11 * 9 = 99

Question 3: 77 - 63 = 88 - 74 > 0

Question 4: 4 * 4 = 16

Question 5: 7 * 7 = 49. 12/6 = 2

Question 6: 4 * 3 = 12. 56 + 7 = 63

Question 7: 9 = 25 - 16. 1 * 6 = 6

Question 8: 3 + 1 = 4. 8 + 15 = 23 - 0

Question 9: 3 + 28 = 31

Question 10: 4 + 1 = 3 + 2

This quiz was reviewed by FunTrivia editor Tizzabelle before going online.

Any errors found in FunTrivia content are routinely corrected through our feedback system.

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