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Quiz about Follow My 9 Directions for 10
Quiz about Follow My 9 Directions for 10

Follow My 9 Directions for 10 Trivia Quiz


You're invited to delve into my second homage to eburge's classic "Follow My Directions" series. This time it is combined with a salute to minch's "9 for 10" series. Enjoy!

A multiple-choice quiz by gentlegiant17. Estimated time: 10 mins.
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Time
10 mins
Type
Multiple Choice
Quiz #
318,615
Updated
Dec 03 21
# Qns
10
Difficulty
Difficult
Avg Score
4 / 10
Plays
236
Question 1 of 10
1. In this quiz, "the ordinal number" of a certain letter is simply its place in the English alphabet.
For example, the ordinal number of C is 3. The ordinal number of M is 13. The ordinal number of Z is 26.

The natural values for ordinal numbers are 1 to 26. However, numbers larger than 26 as well as negative numbers are also legal ordinal number values. The only thing that matters is the remainder of dividing the number in question by 26. In mathematical lingo this is expressed by noting that ordinal numbers are "modulo 26".

For example, the ordinal numbers 55 and -23 also correspond to the letter C since both have a remainder of 3 when divided into 26: 55=(2*26)+3 (or 55mod26=3 in arithmetic notation) and -23=(-1*26)+3 (or -23mod26=3).

Take a look at the string PRIMENUMBER - which one of its letters has the smallest ordinal number?

Answer: (One letter)
Question 2 of 10
2. Subtract 6 from the string PRIMENUMBER.

Which is the third letter of the resultant string?

Note: subtraction from a word is done simply by operating on its ordinal number array: write down the ordinal numbers corresponding to each of the word's letters and subtract each one of them in order to receive the ordinal numbers of the resultant word.

Example: subtracting 6 from DOG gives XIA (DOG-6=XIA)
DOG=(4,15,7)
DOG-6=(4-6,15-6,7-6)=(-2,9,1)
(-2,9,1)mod26=(-1*26+24,9,1)mod26=(24,9,1)
(24,9,1)=XIA

Answer: (One letter)
Question 3 of 10
3. Even-divide the string you now have by 2.

Which is the first letter of the resultant string?

Note: even-dividing a string by 2 is done by halving letters whose ordinal number is even while leaving untouched letters whose ordinal number is odd. The notation of even-division is "//".

Example: even-halving DOG gives BOG (DOG//2=BOG)
DOG=(4,15,7)
DOG//2=(4/2,15,7)=(2,15,7)
(2,15,7)=BOG

Answer: (One letter)
Question 4 of 10
4. Even-add 1 to the string you now have.

Which is the letter which appears the most times in the resultant string?

Note: even-adding 1 to a string is done by adding 1 to letters whose ordinal number is even while leaving untouched letters whose ordinal number is odd. The notation of even-addition is "++".

Example: even-adding 1 to DOG gives EOG (DOG++1=EOG)
DOG=(4,15,7)
DOG++1=(4+1,15,7)=(5,15,7)
(5,15,7)=EOG

Answer: (One letter)
Question 5 of 10
5. Remove the letters which are evenly divisible by 3 from the string you now have.

Which is the only letter that appears once in the resultant string?

Note: a letter is evenly divisible by 3 if its ordinal number is.

Example: removing letters evenly divisible by 3 from DOG gives DG
DOG=(4,15,7) where only 15 is evenly divisible by 3 and the O is removed
DOG-O=DG

Answer: (One letter)
Question 6 of 10
6. Remove the letters which appear exactly twice from the string you now have.

Which is the letter whose ordinal number corresponds to the addition of the ordinal numbers of the five letters of the resultant string?

Note: remember that ordinal numbers are modulo 26.

Example: addition of the ordinal numbers of the word DOGMA gives the letter N
DOGMA=(4,15,7,13,1)
4+15+7+13+1=40
40mod26=14 (since 40=1*26+14)
The letter whose ordinal number is 14 is N

Answer: (One letter)
Question 7 of 10
7. Square the string you now have.

Which is the fourth letter of the resultant string?

Note: remember that ordinal numbers are modulo 26.

Example: squaring DOG gives PQW (DOG2=PQW)
DOG=(4,15,7)
DOG2=(42,152,72)=(16,225,49)
(16,225,49)mod26=(16,8*26+17,1*26+23)mod26=(16,17,23)
(16,17,23)=PQW

Answer: (One letter)
Question 8 of 10
8. Remove the four identical letters from the string you now have.
Multiply the remaining letter by 21.

Which is the resultant letter?

Answer: (One letter)
Question 9 of 10
9. You've worked hard enough to get here. All you have to do in this step is write down the letter whose ordinal number is bigger by 4 than the one of letter you now have.

Which is the resultant letter?

Answer: (One letter)
Question 10 of 10
10. Time for the 9 for 10 bit.
Take a long hard look at the answers you have for the first nine questions.
Don't forget where you started.

Which is the number that comes next in the series formed by a certain numerical property of the first nine answers?

Answer: (One number - 2 digits)

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Quiz Answer Key and Fun Facts
1. In this quiz, "the ordinal number" of a certain letter is simply its place in the English alphabet. For example, the ordinal number of C is 3. The ordinal number of M is 13. The ordinal number of Z is 26. The natural values for ordinal numbers are 1 to 26. However, numbers larger than 26 as well as negative numbers are also legal ordinal number values. The only thing that matters is the remainder of dividing the number in question by 26. In mathematical lingo this is expressed by noting that ordinal numbers are "modulo 26". For example, the ordinal numbers 55 and -23 also correspond to the letter C since both have a remainder of 3 when divided into 26: 55=(2*26)+3 (or 55mod26=3 in arithmetic notation) and -23=(-1*26)+3 (or -23mod26=3). Take a look at the string PRIMENUMBER - which one of its letters has the smallest ordinal number?

Answer: B

In other words, you were looking for the letter which is closest to the start of the alphabet.
A is not in PRIMENUMBER, but B is.
2. Subtract 6 from the string PRIMENUMBER. Which is the third letter of the resultant string? Note: subtraction from a word is done simply by operating on its ordinal number array: write down the ordinal numbers corresponding to each of the word's letters and subtract each one of them in order to receive the ordinal numbers of the resultant word. Example: subtracting 6 from DOG gives XIA (DOG-6=XIA) DOG=(4,15,7) DOG-6=(4-6,15-6,7-6)=(-2,9,1) (-2,9,1)mod26=(-1*26+24,9,1)mod26=(24,9,1) (24,9,1)=XIA

Answer: C

Step by step:

PRIMENUMBER=(16,18,9,13,5,14,21,13,2,5,18)
PRIMENUMBER-6=(10,12,3,7,-1,8,15,7,-4,-1,12)
(10,12,3,7,-1,8,15,7,-4,-1,12)mod26=(10,12,3,7,25,8,15,7,22,25,12)
(10,12,3,7,25,8,15,7,22,25,12)=JLCGYHOGVYL

The third letter of JLCGYHOGVYL is C.
3. Even-divide the string you now have by 2. Which is the first letter of the resultant string? Note: even-dividing a string by 2 is done by halving letters whose ordinal number is even while leaving untouched letters whose ordinal number is odd. The notation of even-division is "//". Example: even-halving DOG gives BOG (DOG//2=BOG) DOG=(4,15,7) DOG//2=(4/2,15,7)=(2,15,7) (2,15,7)=BOG

Answer: E

Step by step:

JLCGYHOGVYL=(10,12,3,7,25,8,15,7,22,25,12)
JLCGYHOGVYL//2=(5,6,3,7,25,4,15,7,11,25,6)
(5,6,3,7,25,4,15,7,11,25,6)=EFCGYDOGKYF

The first letter of EFCGYDOGKYF is E.
4. Even-add 1 to the string you now have. Which is the letter which appears the most times in the resultant string? Note: even-adding 1 to a string is done by adding 1 to letters whose ordinal number is even while leaving untouched letters whose ordinal number is odd. The notation of even-addition is "++". Example: even-adding 1 to DOG gives EOG (DOG++1=EOG) DOG=(4,15,7) DOG++1=(4+1,15,7)=(5,15,7) (5,15,7)=EOG

Answer: G

Step by step:

EFCGYDOGKYF=(5,6,3,7,25,4,15,7,11,25,6)
EFCGYDOGKYF++1=(5,7,3,7,25,5,15,7,11,25,7)
(5,7,3,7,25,5,15,7,11,25,7)=EGCGYEOGKYG

The letter which appears the most times in EGCGYEOGKYG is G.
5. Remove the letters which are evenly divisible by 3 from the string you now have. Which is the only letter that appears once in the resultant string? Note: a letter is evenly divisible by 3 if its ordinal number is. Example: removing letters evenly divisible by 3 from DOG gives DG DOG=(4,15,7) where only 15 is evenly divisible by 3 and the O is removed DOG-O=DG

Answer: K

Step by step:

EGCGYEOGKYG=(5,7,3,7,25,5,15,7,11,25,7)
C (ordinal number 3) and O (ordinal number 15) should be removed
EGCGYEOGKYG-CO=EGGYEGKYG

The only letter which appears once in EGGYEGKYG is K.
6. Remove the letters which appear exactly twice from the string you now have. Which is the letter whose ordinal number corresponds to the addition of the ordinal numbers of the five letters of the resultant string? Note: remember that ordinal numbers are modulo 26. Example: addition of the ordinal numbers of the word DOGMA gives the letter N DOGMA=(4,15,7,13,1) 4+15+7+13+1=40 40mod26=14 (since 40=1*26+14) The letter whose ordinal number is 14 is N

Answer: M

Step by step:

EGGYEGKYG-EEYY=GGGKG
Adding up the five ordinal numbers of GGGKG gives 39 (7+7+7+11+7)
39mod26=13 (since 39=1*26+13)

13 is the ordinal number of the letter M.
7. Square the string you now have. Which is the fourth letter of the resultant string? Note: remember that ordinal numbers are modulo 26. Example: squaring DOG gives PQW (DOG2=PQW) DOG=(4,15,7) DOG2=(42,152,72)=(16,225,49) (16,225,49)mod26=(16,8*26+17,1*26+23)mod26=(16,17,23) (16,17,23)=PQW

Answer: Q

Step by step:

GGGKG=(7,7,7,11,7)
GGGKG^2=(49,49,49,121,49)
(49,49,49,121,49)mod26=(23,23,23,17,23)
(23,23,23,17,23)=WWWQW

The fourth letter of WWWQW is Q.
8. Remove the four identical letters from the string you now have. Multiply the remaining letter by 21. Which is the resultant letter?

Answer: S

Step by step:

WWWQW-WWWW=Q
Q=21
17*21=357
357mod26=19 (since 357=13*26+19)

19 is the ordinal number of the letter S.
9. You've worked hard enough to get here. All you have to do in this step is write down the letter whose ordinal number is bigger by 4 than the one of letter you now have. Which is the resultant letter?

Answer: W

Step by step:

S=19
19+4=23

23 is the ordinal number of the letter W.
10. Time for the 9 for 10 bit. Take a long hard look at the answers you have for the first nine questions. Don't forget where you started. Which is the number that comes next in the series formed by a certain numerical property of the first nine answers?

Answer: 29

Step by step:

The first nine answers are: B,C,E,G,K,M,Q,S,W.
Appropriately for this quiz, the numerical property in question is the ordinal number.
The ordinal numbers of the first nine answers are 2,3,5,7,11,13,17,19,23.
These are the first nine prime numbers.
The initial string of the quiz was PRIMENUMBER (was it a good hint?).
The answer to this question is thus the tenth prime number - 29.
Source: Author gentlegiant17

This quiz was reviewed by FunTrivia editor crisw before going online.
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