A multiple-choice quiz
by xxharryxx.
Estimated time: 5 mins.

Scroll down to the bottom for the answer key.

Quiz Answer Key and Fun Facts

Answer:
**1/2**

There are six numbers on a die: 1, 2, 3, 4, 5, and 6. There are three even numbers on the die: 2, 4, and 6. 3 out of six numbers are even. 3/6 reduces to 1/2.

There are six numbers on a die: 1, 2, 3, 4, 5, and 6. There are three even numbers on the die: 2, 4, and 6. 3 out of six numbers are even. 3/6 reduces to 1/2.

Answer:
**3/4**

A quick way of going about this problem is determining the probability that one of your friend's outcomes will appear. The probability of multiple events happening is equal to the product of the probability of each single event. The probability of flipping heads is 1/2, so the probability of flipping three heads in a row would be (1/2 * 1/2 * 1/2), or 1/8.

The same thing occurs in the tails. (1/2 * 1/2 * 1/2) is equal to 1/8. The probability of your friend winning is 2/8, or 1/4. Subtract 1/4 from 1 to get 3/4, the probability of you winning.

A quick way of going about this problem is determining the probability that one of your friend's outcomes will appear. The probability of multiple events happening is equal to the product of the probability of each single event. The probability of flipping heads is 1/2, so the probability of flipping three heads in a row would be (1/2 * 1/2 * 1/2), or 1/8.

The same thing occurs in the tails. (1/2 * 1/2 * 1/2) is equal to 1/8. The probability of your friend winning is 2/8, or 1/4. Subtract 1/4 from 1 to get 3/4, the probability of you winning.

Answer:
**1/5**

Even though the spinner just landed on 1, it doesn't change the outcome of the next spin. There is only one way to spin a 1, and there are five spots for the spinner to land on. The probability is 1/5.

Even though the spinner just landed on 1, it doesn't change the outcome of the next spin. There is only one way to spin a 1, and there are five spots for the spinner to land on. The probability is 1/5.

Answer:
**1/64**

You have to flip heads five times in a row to win $1000. The probability of flipping heads once is 1/2, so the probability of flipping heads five times would be (1/2 * 1/2 * 1/2 * 1/2 * 1/2), or 1/32. However, the game is not over yet. In order to end the game, you must now flip tails. The probability of that is 1/2. 1/2 * 1/32 = 1/64.

You have to flip heads five times in a row to win $1000. The probability of flipping heads once is 1/2, so the probability of flipping heads five times would be (1/2 * 1/2 * 1/2 * 1/2 * 1/2), or 1/32. However, the game is not over yet. In order to end the game, you must now flip tails. The probability of that is 1/2. 1/2 * 1/32 = 1/64.

Answer:
**1/2**

A composite number is a number with more than two factors. We see that 4, 6, 8, 9, 10, and 12 are composite when we look at their factors. 6 out of the 12 numbers are composite. 6/12 simplifies to 1/2.

A composite number is a number with more than two factors. We see that 4, 6, 8, 9, 10, and 12 are composite when we look at their factors. 6 out of the 12 numbers are composite. 6/12 simplifies to 1/2.

Answer:
**45 **

15 blue marbles has to be a fraction of the total amount of marbles. It is the fraction that the red and yellow marbles do not take up. To find the fraction, first convert 20% to a fraction. 20% is equal to 1/5. 7/15 + 1/5 (or 3/15) is equal to 10/15 or 2/3.

The red and yellow marbles take up 2/3 of the bag, so we know that the blue marbles must take up the remaining third of the bag. You can now set up a formula using the variable x, where x equals the total number of marbles in the bag. 1/3 * x = 15. Multiply each side by 3 (or divide by 1/3) to get x = 45 marbles.

15 blue marbles has to be a fraction of the total amount of marbles. It is the fraction that the red and yellow marbles do not take up. To find the fraction, first convert 20% to a fraction. 20% is equal to 1/5. 7/15 + 1/5 (or 3/15) is equal to 10/15 or 2/3.

The red and yellow marbles take up 2/3 of the bag, so we know that the blue marbles must take up the remaining third of the bag. You can now set up a formula using the variable x, where x equals the total number of marbles in the bag. 1/3 * x = 15. Multiply each side by 3 (or divide by 1/3) to get x = 45 marbles.

Answer:
**1/18**

The probability of flipping heads is 1/2. The probability of rolling a composite number (4 and 6) is 1/3. The probability of spinning a 2 is 1/3. Multiply: 1/2 * 1/3 * 1/3 is equal to 1/18.

The probability of flipping heads is 1/2. The probability of rolling a composite number (4 and 6) is 1/3. The probability of spinning a 2 is 1/3. Multiply: 1/2 * 1/3 * 1/3 is equal to 1/18.

Answer:
**2/15**

On the first draw, there are four white marbles out of ten. The probability of picking one is 2/5. On the second draw, assuming we picked a white marble, there are three white marbles out of nine total marbles. The probability of picking one is 1/3. Multiply the probabilities of both outcomes together to get 2/15.

On the first draw, there are four white marbles out of ten. The probability of picking one is 2/5. On the second draw, assuming we picked a white marble, there are three white marbles out of nine total marbles. The probability of picking one is 1/3. Multiply the probabilities of both outcomes together to get 2/15.

Answer:
**3/5**

Looking at the factors of 24, we see that 1, 2, 3, 4, 6, and 8 are the factors of 24 that are between one and ten. Six out of the ten numbers between one and ten are factors of 24. 6/10 reduces to 3/5.

Looking at the factors of 24, we see that 1, 2, 3, 4, 6, and 8 are the factors of 24 that are between one and ten. Six out of the ten numbers between one and ten are factors of 24. 6/10 reduces to 3/5.

Answer:
**2/3**

Since the male child could be the first or second child, the easiest way to see this problem would be to list out all possible outcomes. The couple could have a boy, then a boy. They could also have a boy and then a girl. They could have a girl first, and then a boy.

The final combination would be two girls. Since the problem states that at least one child is a boy, the final option of two girls does not work. Looking at our three remaining combinations, two of them have one female. The probability is 2/3.

Since the male child could be the first or second child, the easiest way to see this problem would be to list out all possible outcomes. The couple could have a boy, then a boy. They could also have a boy and then a girl. They could have a girl first, and then a boy.

The final combination would be two girls. Since the problem states that at least one child is a boy, the final option of two girls does not work. Looking at our three remaining combinations, two of them have one female. The probability is 2/3.

This quiz was reviewed by FunTrivia editor crisw before going online.

Any errors found in FunTrivia content are routinely corrected through our feedback system.

Most Recent Scores

Jun 03 2023
:
Guest 209: 4/10Jun 02 2023 : ebanks120: 4/10

Jun 01 2023 : Guest 122: 8/10

Jun 01 2023 : Guest 198: 3/10

Jun 01 2023 : Guest 199: 3/10

May 30 2023 : Guest 174: 7/10

May 30 2023 : Guest 204: 7/10

May 30 2023 : Guest 185: 1/10

May 28 2023 : Guest 202: 2/10

Score Distribution

Related Quizzes

1. **Probability of Answering This Quiz Correctly** Average

2.**Statistics 101** Tough

3.**Pick A Card, Any Card!** Tough

4.**High School Finite Math** Tough

5.**Mean, Mode and Median** Average

6.**The Mathematics of FunTrivia-Like Games** Tough

7.**Dice Probabilities** Tough

8.**Simple Statistics** Average

9.**A Matter of Probability...** Tough

10.**Theoretical Basic Probability** Tough

11.**Iggy's Probability Quiz 2** Very Difficult

12.**Shelly's Sunday: A Probability Quiz** Very Difficult

2.

3.

4.

5.

6.

7.

8.

9.

10.

11.

12.

Referenced Topics

For Children
Science
Math
Blue
Statistics and Probability
White
Other Destinations

Explore Other Quizzes by Go to

More

FunTrivia